Model 3 Opening both taps and leaks Practice Questions Answers Test with Solutions & More Shortcuts

Question : 16

Two pipes A and B can fill a tank with water in 30 minutes and 45 minutes respectively. The water pipe C can empty the tank in 36 minutes. First A and B are opened. After 12 minutes C is opened. Total time (in minutes) in which the tank will be filled up is :

a) 24

b) 36

c) 30

d) 12

Answer: (a)

Using Rule 1 and 2,

Part of tank filled by pipes A and B in 1 minute

= $1/30 + 1/45 = {3 + 2}/90 = 1/18$ part

Part of tank filled in 12 minutes

= $12/18 = 2/3$ part

Remaining part

= $1 - 2/3 = 1/3$ part

When pipe C is opened,

Part of tank filled by all three pipes

= $1/30 + 1/45 - 1/36$

= ${6 + 4 - 5}/180 = 5/180 = 1/36$

Time taken in filling $1/3$ part

= $1/3$ × 36 = 12 minutes

Total time = 12 + 12 = 24 miuntes

Question : 17 [SSC MTS 2013]

An empty tank can be filled by pipe A in 4 hours and by pipe B in 6 hours. If the two pipes are opened for 1 hour each alternately with first opening pipe A, then the tank will be filled in

a) 5$1/2$ hours

b) 4$2/3$ hours

c) 1$3/4$ hours

d) 2$3/5$ hours

Answer: (b)

Part of the tank filled in first 2 hours

= $1/4 + 1/6 = {3 + 2}/12 = 5/12$ Part

Part of the tank filled in first 4 hours

= ${2 × 5}/12$ parts= $5/6$ parts

Remaining part = $1 - 5/6 = 1/6$

Now it is the turn of pipe A

Time taken to fill $1/4$ part = 1 hour

Time taken to fill $1/6$ part

= $1/6 × 4 = 2/3$ hour

Total time = 4 + $2/3 = 4{2}/3$ hours

Question : 18 [SSC CHSL 2013]

Three pipes A, B and C can fill a tank in 6 hours. After working together for 2 hours, C is closed and A and B fill the tank in 8 hours. The time (in hours) in which the tank can be filled by pipe C alone is

a) 9

b) 8

c) 10

d) 12

Answer: (d)

Part of the tank filled by

(A + B + C) in 1 hour = $1/6$

Part of tank filled by these in 2 hours

= $2/6 = 1/3$

Remaining part = $1 - 1/3 = 2/3$

Time taken by A and B in filling

$2/3$ rd part = 8 hours

Time taken by A and B in filling the whole tank

= ${8 × 3}/2$ = 12 hours

Part of tank filled by C in an hour

= $1/6 - 1/12 = 1/12$

Hence, required time = 12 hours

Question : 19 [SSC CGL Prelim 2003]

A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely ?

a) 3 hours 45 minutes

b) 3 hours 15 minutes

c) 4 hours

d) 4 hours 15 minutes

Answer: (a)

A tap can fill the tank in 6 hours. In filling the tank to its half, time required = 3 hours.

Remaining part = $1/2$

Since, 1 tap takes 6 hours to fill the tank

Time taken by 4 taps take to fill $1/2$ of the tank

= $6/4 × 1/2 = 3/4$ hour

Total time = $3 + 3/4$

= $3{3}/4$ hours = 3 hours 45 minutes

Question : 20

Three pipes A, B and C can fill a tank in 6 hours. After working together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is

a) 16

b) 14

c) 10

d) 12

Answer: (b)

A, B and C together fill the tank in 6 hours.

Part of the tank filled in 1 hour by (A + B + C) = $1/6$

Part of the tank filled in 2 hours by all three pipes

= $2/6 = 1/3$

Remaining empty part

= $1 - 1/3 = 2/3$

This $2/3$ part is filled by (A + B).

Time taken by (A + B) to fill the fully empty tank

= ${7 × 3}/2 = 21/2$ hours

Part of tank filled by C in 1 hour

= $1/6 - 2/21 = {7 - 4}/42 = 3/42 = 1/14$

∴ Required time = 14 hours.

IMPORTANT quantitative aptitude EXERCISES

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